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I recently built and started up a small CIP plant and came across this simple titration calculation recommended by A K Williams. The math is simple and I assume the formula is accurate - but would like to confirm. As follows:
1. make up 1 liter of solution: distilled water + 13.07 grams of silver nitrate
2. titrate as normal using 100ml of filtrate / sample
3. the ml of silver nitrate consumed divided by 10 = the % of free cyanide. Example: 1.5 ml of silver nitrate consumed = .15% of free cyanide
Second question: to maintain even a tiny percentage of free cyanide in the last tank is adequate yes?
Thanks in advance!